Question

It is a mass of 4 kg is dropped from a height of 100 m, what is its velocity when its touches the ground

Answer 1

Answer:

v=44.7m/s

Explanation:

vf=v(final velocity).

vi=u(initial velocity).

g=acceleration due to gravity.

Given:

m=4kg

h=100m

u=0m/s

To find:

v=?

Solution:

2gh=v^2-u^2

2*10*100=v^2

2000=v^2

v=√2000

v=44.71m/s.