Math, asked by caprisiajgraham, 9 months ago

It is a square pyramid with a base edge of 706 feet and an original height of 470 feet.

What was the original volume of the Khafre Pyramid? Show your work.

Answers

Answered by AditiHegde
0

The original volume of the Khafre Pyramid, given it is a square pyramid with a base edge of 706 feet and an original height of 470 feet is 7.81 × 10^7 ft³

Given,

A square pyramid with a base edge of 706 feet and an original height of 470 feet.

The original volume of the Khafre Pyramid is given by,

Given,

Base edge = a = 706 ft

Height = h = 470 ft

The formula for calculating the volume of a right square pyramid is given by,

V = a²(h/3)

where, V = volume of the right square pyramid

V = 706² ( 470 / 3)

= 706² ( 156.67)

= 7.81 × 10^7 ft³

Answered by dheerajk1912
0

The original volume of the square pyramid is 78088306.67 feet³

Step-by-step explanation:

  • Here it given about square pyramid.
  • We know that base of square pyramid is square.

        Side of square (a) = 706 feet

        Height of square pyramid(H) = 470 feet

  • Area of base = Area of square = a²=706² = 498436 feet²
  • We know the formula of volume of pyramid

        \mathbf{Volume \ of \ pyramid\ (V)=\frac{1}{3}\times Area\ of\ base \times Height}

  • \mathbf{Volume \ of \ square\  pyramid\ (V)=\frac{1}{3}\times  498436\times 470}

        On solving, we get

        Volume of square pyramid = 78088306.67 feet³

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