Question

It is an altitude of an isosceles triangle abc in which ab is equal to ac show that first ad bisects bc second ad bisects angle a

Answer 1

By congruency we can find both answer.
In triangle abc having altitude ad
So
Ad is common
Ab is equal to ac(given)
Angle abd is equal to angle acd (by theorem)
Hence
Abd is congruent to acd.
"don't mind capital and small letters"

Answer 2

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