Question

It is because of inability of ns² electrons of the valence shell to participate in bonding that:-
(a) Sn²⁺ is oxidising while Pb⁴⁺ is reducing
(b) Sn²⁺ and Pb²⁺ are both oxidising and reducing
(c) Sn⁴⁺ is reducing while Pb⁴⁺ is oxidising
(d) Sn²⁺ is reducing while Pb⁴⁺ is oxidising

Answer 1

Answer:

Explanation:

nert pair effect -

The phenomenon in which outer shell s electrons (ns2) penetrate to (n-1) d-electrons and thus become closer to nucleus and are more effectively pulled by the nucleus

- wherein

This results in less availability of ns2 electrons pair for bonding or ns2 electron pair becomes inert.

 Stability of S_{n}^{+4}> S_{n}^{2+}  but stability of P_{b}^{2+}> P_{b}^{+4}  which result S_{m}^{2+}  is reducing while P_{b}^{+4}  is oxidising in nature.

Option 1)

Sn2+ is reducing while Pb4+ is oxidising

Correct option

Option 2)

Sn2+ is oxidising while Pb4+ is reducing

Incorrect option

Option 3)

Sn2+ and Pb2+ are both oxidising and reducing

Incorrect option

Option 4)

Sn4+ is reducing while Pb4+ is oxidising

Incorrect option

Answer 2

option 1 sn2+ is oxidising while pb4+ is reducing