Math, asked by Suhana900, 1 month ago

It is common that government revise fares time to time on various factors such as inflation ,different type of vehicles, auto rickshaws , taxis, radio cab etc .The auto charges in a city comprise of a fixed charge together with the charge for the distance covered . Study the following situation. In a city for a journey of 8 km the charge paid is Rs 91 and for a journey of 14 km the charge paid is Rs 145

I)If the fixed charge is Rs x and the running charges is Rs y per km ,then the pair of linear equations representing the situation is *

a) X + 8 y = 91 , x + 14 y = 145
b) X + 8 y = 145 , x + 14 y = 91
c) 8X + y = 91 , 14 x + y = 145
d) 8X + y = 145 , 14x + y = 91

II)What is the nature of graph

a) Intersecting lines
b) parallel
c) coincident
d) None of the above

III)Number of minimum points required to draw a line *
a) 1
b) 2
c) 3
d) 4
IV) What is the fixed charge in this situation *

a) 9
b) 19
c)29
d)39

V) What is the charge per km in this situation.

a) 20
b) 19
c) 29
d) 30​

Answers

Answered by 8apavneetbissingh
1

Answer:

  1. a
  2. d
  3. b
  4. a
  5. c

this is your answer

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