Physics, asked by Bhavana7358, 11 months ago

It is easier ionize hydrogen as compared to deuterium, because

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Answered by malihabatul23
1

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High resolution energy spectra of electrons and ions resulting from thermal energy collisions of hydrogen and deuterium atoms with state-selected metastable Ne(Ne(3s3P2,3P0) atoms are reported. The electron spectra for Ne(3P2)+H(D) are very broad: The high energy part due to formation of NeH+ (NeD+) bound states (associative ionization), amounts to about 30% of the ionizing events, whereas the dominant part of the spectrum including a prominent low-energy peak is due to Penning ionization out of a strongly-attractive entrance potential curve. Comparison of the spectra with quantum mechanical fit calculations yields fairly accurate information on this potential, in particular its well depthD e [Ne(3P2)−H,D]= 2.0(1) eV. The spectra for Ne(3P0)+H, D are comparatively narrow with much lower cross sections than the one for the Ne(3P2) state. The corresponding entrance channel is a weakly bound van der Waals molecule with a well depth below 0.1 eV. A perturbation calculation of the Ne(3s)+H(1s) potential energy curves at large distances explains the observed difference between the Ne(3P2)+H(D) and Ne(3P0)+H(D) systems. Symmetry arguments are given that the major contribution to the Ne(3P2)+H(D) spectra is due to the2Σ potential.

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