It is estimated that there are eight times as many deer in a forest as there are on the bank of river near the forest.if the total number of deer in the forest and o the bank of the river is 153,find the number of deer in the forest
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let the no deers in the bank be X
now,no of deers in the forest will be 8x
total no of deers =8x +X =153
X=17
therefore number of deers in forest is 8×17 which is136
now,no of deers in the forest will be 8x
total no of deers =8x +X =153
X=17
therefore number of deers in forest is 8×17 which is136
kavya1011:
I had tried the same thig but the answer at back side of the book
Answered by
1
let no of deer on bank of river =X
then deer in the forest = 8x
x+8x = 153 given
9x =153
x=17
dear in forest = 8x
8×17
136
then deer in the forest = 8x
x+8x = 153 given
9x =153
x=17
dear in forest = 8x
8×17
136
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