Question

It is found on heating a gas, its volume increases by 50% and pressure
decreases to 60% of its original value. If the original temperature was -15oC, find
the temperature to which it was heated.

Answer 1

You can use the equation for the general transformation of the ideal gas:

pV/T = const.

So pV/T = fpV(1+k)/T',

Where f = 0.6 and k = 0.5

You get T' = Tf(1+k)

T = 273 - 15 = 258 K

T' = 258*0.6*1.5 = 232.2 K

t’ = -40.8 degrees Celsius.

Or you can write

pV = nu*RT

0.6p*1.5V = nu*RT' => 0.9pV = nu*RT'

So 0.9T = T' => T' = 232.2 K

The gas is not heated.

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Answer 2

Answer:

You can use the equation for the general transformation of the ideal gas:

pV/T=const.

So pV/T = fpV(1+k)/T',

Where f = 0.6 and k = 0.5

You get T' = Tf(1+k)

T = 273 - 15 = 258 K

T' = 258*0.6*1.5 = 232.2 K

t' = -40.8 degrees Celsius.

Or you can write

PV = nu*RT

0.6p*1.5V = nu*RT' => 0.9pV = nu*RT'

So 0.9T = T' => T' = 232.2 K

The gas is not heated.