It is found that the difference of two unit vectors is also a unit vector. The magnitude of their sum will be a
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Answer:
√3
Explanation:
(|a-b|)^2 =1
=> a^2 + b^2 - 2 ab costheta = 1
=> -2 ab costheta = 1 - 2 = -1
cos theta = +1/2
theta = 60 deg
|a+b| = √ 1 + 1 + 2.1.1 cos 60
= √1 + 1 + 1
= √3
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