Question

It is found that the difference of two unit vectors is also a unit vector. The magnitude of their sum will be a​

Answer 1

Answer:

√3

Explanation:

(|a-b|)^2 =1

=> a^2 + b^2 - 2 ab costheta = 1

=> -2 ab costheta = 1 - 2 = -1

cos theta = +1/2

theta = 60 deg

|a+b| = √ 1 + 1 + 2.1.1 cos 60

= √1 + 1 + 1

= √3