Question

it Is from ICSE syllabus friends​

Answer 1

˙˙˙:sı ɹǝʍsuɐ ǝɥʇ

˙˙˙:sı ɹǝʍsuɐ ǝɥʇ

Answer 2

˙pɹɐoq ǝsɔᴉ uᴉ ǝɹɐ noʎ ʇɐɥʇ ʍouʞ ᴉ ɥɐǝʎ

(: noʎ sdlǝɥ sᴉɥʇ ǝdoɥ :)

${\large\blue{\mathbb\fcolorbox{aqua}{darkblue}{\star \: QUESTION:}}}$

❥︎ Find:-

(i) 5/4+(-11/4)

(ii) (-6/13)-(-7/15)

(iii) (1/8)÷(3/4)

(iv) (3/11)×(2/5).

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${\large\blue{\mathbb\fcolorbox{aqua}{darkblue}{\star \: ANSWER:}}}$

❥︎ Solutions:-

$\begin{lgathered}(i) \: \frac{5}{4} + ( - \frac{11}{4} ) \\ \\ = \frac{5}{4} - \frac{11}{4} \\ \\ = \frac{5 - 11}{4} \\ \\ = \frac{ - 6}{4} \\ \\ = {\fbox { \frac{ - 3}{2}}}\end{lgathered}$

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$\begin{lgathered}(ii)\: (- \frac{6}{13}) - ( - \frac{7}{15} ) \\ \\ =( - \frac{6}{13} )+ ( \frac{7}{15} ) \\ \\ = - \frac{(6)(15)}{(13)(15)} + \frac{(7)(13)}{(15)(13)} \: [ Taking \: L.C.M.] \\ \\ = - \frac{90}{195} + \frac{91}{195} \\ \\ = \frac{-90+91}{195} \\ \\ = {\fbox { \frac{1 }{195 }}}\end{lgathered}$

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$\begin{lgathered}(iii) \: \frac{1}{8} ÷ \frac{3}{4} \\ \\ = \frac{1}{8} × \frac{4}{3} \\ \\ = \frac{4}{4×2 × 3} \\ \\ = \frac{1}{2×3} \\ \\ = {\fbox { \frac{1}{6}}}\end{lgathered}$

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$\begin{lgathered}(iv) \: \frac{3}{11} × \frac{2}{5} \\ \\ = \frac{3×2}{11×5} \\ \\ = {\fbox { \frac{6}{55}}}\end{lgathered}$

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${\pink{\huge\underbrace{Thanks \: Please}}}$