it is game the ∆ ABC = ∆ FDE and AB = 4 cm , LB = 40° and LE = 60° then which of the following is true
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Answer:
In △ABC
∠A=80
o
∠B=40
o
∠A+∠B+∠C=180
o
80+40+∠C=180
o
∠C=60
o
Now, △ABC≅△FDE
Thus, by CPCT (Corresponding parts of congruent triangles are congruent),
∠A=∠F=80
o
∠B=∠D=40
o
∠C=∠E=60
o
AB=FD=5cm
BC=DE
AC=EF
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i think 2 nd............
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