Question

it is given in a group of 3 students , the probability that the 2 student have same birthday is 0.008.what is the probability that the student not having the same birthday?​

Answer 1

Step-by-step explanation:

probability of 2 students having same birthday = 0.008

Therefore probability of the students not having the same birthday = 1 - 0.008 = 0.992

Answer 2

The probability that students not having the same birthday is 0.992

Step-by-step explanation:

Given:

probability that 2 students have the same birthday is 0.008

To find out:

probability that the students do not have the same birthday

Solution:

Let E be an event such that

E: 2 students having the same birthday

Then

Probability of E

$P(E)=0.008$

Probability that 2 students not having the same birthday

$P(\bar E)=1-P(E)$

$\implies P(\bar E)=1-0.008$

$\implies P(\bar E)=0.992$

Hope this answer is helpful.

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Q: It is given that in a group of 3 students, the probability of 2 students not having the same birthday is 0.992. What is the probability that the 2 students have the same birthday?

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