It is given that 3a+5b=2c,then find the value 27a^3+125b^3-8c^3 if abc =2
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27a³ + 8b³ - 125c³= (3a)³+ (2b)³ + (-5c)³
3a + 2b = 5c
3a + 2b - 5c = 0
Hence, (3a)³ + (2b)^3 + (-5c)³ = 3 (3a) (2b)(-5c)
= -90 abc = -90 x 0 = 0.ans...
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