• It is given that 3a+5b=2c, then find the value 27a3+125b3-8c3 if abc =2?
Answers
Step-by-step explanation:
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Answer:
-180
Step-by-step explanation:
(x+y+z)³ = x³+y³+z³+3(x+y)(y+z)(z+x)
Assuming
x = 3a, y = 5b and z = -2c
We have x+y+z = 0 ( bringing 2c from RHS to LHS)
x³+y³+z³ = (x+y+z)³ - 3(x+y)(y+z)(z+x)
Substituting values and deriving from x+y+z = 0 we have
x³+y³+z³ = 0 - 3(-z)(-x)(-y) = 3xyz
Replacing original values in x, y, z we have
27a³+125b³-8c³ = 3(3a)(5b)(-2c) = -90abc
27a³+125b³-8c³ = -90 * 2 = -180