Physics, asked by sonuapsr1115, 7 months ago

it is given that A=B^2 .if A=100+-0.20then B is equal to

Answers

Answered by maggie42
0

Answer:

B = +/-(10 +/- 0.01)

Explanation:

it is given that A=B^2 if A=100+- 0.20 then B is equal to

let say B = X +/- y

then B^2 = (X +/- y)^2

= X^2 +/- 2xy

X^2 = 100

=> X = +/- 10

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