it is given that A=B^2 .if A=100+-0.20then B is equal to
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Answer:
B = +/-(10 +/- 0.01)
Explanation:
it is given that A=B^2 if A=100+- 0.20 then B is equal to
let say B = X +/- y
then B^2 = (X +/- y)^2
= X^2 +/- 2xy
X^2 = 100
=> X = +/- 10
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