It is given that a family of 2 children has a girl, what is the probability that the other child
also a girl?
(a) 0.50
(b) 0.25
(c) 1/3
(d) 2/3
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Answer:
(c) 1/3
Step-by-step explanation:
let A be the event that any one child is girl.
and B is the event that both are girls.
now,
sample space= {bb, bg, gb, gg}
n(A)= {bg, gb, gg}
n(B)= {gg}
p(A)= 3/4
p(B)= 1/4
n(A∩B)= {gg}
p(A∩B)= 1/4
now, probability of having a girl given that the other child is already a girl =
p(B/A)= p(A∩B)/p(A)
= (1/4)/(3/4)
= 1/3
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