Question

It is given that AB parallel DE . Find the value of y, if ABC = 110° and CDE = 100°​

Answer 1

Answer:

30

Step-by-step explanation:

abd=dab

b=180-110

70

d=180-100

80

now bcd is a triangle

we know the value of b and d

b+d+c=180

70+80+c=180

c=30

Answer 2

Answer:

The value of y is 30 degree

Step-by-step explanation:

Given:

• In the is given that AB parallel DE.
• ABC = 110° and CDE = 100°​

To find: The value of y

Solution:

In the is given that AB parallel DE.

Alternate interior angle are always equal, and the sum of the angle formed on a straight line is always 180

Sum of all angles of a tringle = 180

Given that

AB || DE

∠ABC = 110

∠CDE = 100

Co-interior angles are the interior angles and it sums up to 180 degrees.

It means that the sum of two interior angles, which are on the same side of transversal is supplementary.

∠ABC = 110

Co interior angles as PQ || AB

⇒∠PCB = 70

∠CDE = 100

co-interior angles as PQ || DE)

∠QCD = 80

Since PQ is the straight line

Add the co interior angles

∠PCB + ∠QCD = 70 + 80

                          = 150

y = 180 - sum of co interior angles

y = 180 - (70 + 80)

y = 180 - 150

y = 30

∠BCD = 30

Final answer:

The value of y is 30 degree

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