Question

It is given that ∆ABC ~ ∆DEF and BC/EF= 1/5 . Then Area of ∆DEF is equal to​

Answer 1

Answer:The correct answer is 25

Step-by-step explanation:

ABC=DEF

so,

AB/DE=AC/DF=BC/EF

then,

AB/DE=AC/DF=1/5

area of the triangle

(BC/EF)^2 = (1/5)^2

                 =1/25

We needed only area of DEF, so 25

Answer 2

The area of ΔDEF is 49.

Given: ΔABC ~ ΔDEF and $\frac{BC}{EF}=\frac{1}{5}$

To find:

Step-by-step explanation:

• The SSS Criterion stands for the premise of side-by-side congruence. If all three sides of one triangle are equal to the three equivalent sides of another triangle, the two triangles are congruent according to this criterion.

⇒ $ar$ΔABC/$ar$ΔDEF$=\frac{AB^{2} }{DC^{2} }$

⇒ $(\frac{1}{5})^{2}=\frac{1}{49}$

Therefore, the area of ΔDEF is equal to $49$.