It is given that ΔABC∼ΔDFE,∠A=300,∠C=400,AB=5cm,AC=8cmandDF=7.5cm.Then, the following is true.
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➠ Given :-
ΔABC∼ΔDFE, ∠A = 30°,∠C = 40°, AB = 5 cm, AC = 8 cm and DF = 7.5 cm
➠ To find :-
DE & ∠F
➠ Solution:-
ΔABC∼ΔDFE
→∠A=30°
→∠C = 40°
→∠B = 110° as sum of all angles of triangle is 180°
ΔABC∼ΔDFE
=> ∠D = ∠A = 30°
∠F = ∠B = 110°
∠E = ∠C = 40°
=> AB/DF = BC/ FE = AC/DE
=> 5 / 7.5 = 8 / DE
=> DE = 12 cm
DE = 12 cm & ∠F = 110°
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