it is given that ∆ ABC =~∆ FDE and AB = 5 cm, angle B = 40° and angle A = 80° find the value of angle E
Answers
Answered by
2
Answer:
✌️60°
This is your answer my friend ❣️
♣️
⏩Hope it is helpful to you ⏪
♣️
⤵️Click here and follow ✌️
Attachments:
Answered by
0
Answer:
hope it is USEFUL
Step-by-step explanation:
Answer
In △ABC
∠A=80o
∠B=40o
∠A+∠B+∠C=180o
80+40+∠C=180o
∠C=60o
Now, △ABC≅△FDE
Thus, by CPCT (Corresponding parts of congruent triangles are congruent),
∠A=∠F=80o
∠B=∠D=40o
∠C=∠E=60o
AB=FD=5cm
BC=DE
AC=EF
Similar questions