It is given that ∆ ABC ≅ ∆ FDE and AB = 5 cm, ∠B = 40° and ∠A = 80°. Then which of the following is true? (b) (c) (d) *
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Answer:
In △ABC
∠A=80
o
∠B=40
o
∠A+∠B+∠C=180
o
80+40+∠C=180
o
∠C=60
o
Now, △ABC≅△FDE
Thus, by CPCT (Corresponding parts of congruent triangles are congruent),
∠A=∠F=80
o
∠B=∠D=40
o
∠C=∠E=60
o
AB=FD=5cm
BC=DE
AC=EF
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Step-by-step explanation:
It is given that ABC ≅ FDE and AB = 5cm, ∠B = 40° and ∠A = 80°, So ∠C = 60°. The sides ABC fall on corresponding equal sides FDE. A corresponding to F, B corresponds to D, and C corresponds to E. So, Only DF = 5cm, ∠E = 60° is true.
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