It is given that ∆ABC ≅ ∆FDE and AB = 6cm, ∠B = 80° and ∠A= 40°. What is the length of side DF of ∆FDE ? What is the measure of ∠E ?
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WE KNOW-
Two triangles are congruent if their corresponding sides are equal in length and their corresponding angles are equal in size.
GIVEN-
Triangle ABC is congruent to triangle FDE
AB=6cm
∠B = 80° and ∠A= 40°
TO DETERMINE-
- the length of side DF of ∆FDE
- the measure of ∠E
SOLUTION-
We know that the sum of 3 angles in a triangle is 180°.
Hence,
∠A+∠B+∠C=180°
=40°+80°+∠C=180°
=∠C=60°
Since triangle ABC is congruent to triangle FDE
so , the corresponding sides are equal in length and the corresponding angles are equal in size for the two triangls ABC and FDE.
therefore,
∠E=∠C=60°
DF=AB=6cm
Hence,
DF=6 cm and ∠E=60∘ is satisfied.
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