Question

It is given that ABC is similar to PQR, with BC/QR = 1/9. Then ar(PRQ)/AR(BCA) is equal to

Answer 1

ΔABC ~ ΔPQR

If two triangles are similar then the ratio of their areas is equal to the square of the ratios of the corresponding sides of the triangles.

ar(BCA)/ar(PQR) = BC²/QR² = 1/9

ar(PRQ)/ar(BCA) = 9 : 1

Hope This Helps You!