it is given that ABC ~PQR with BC/QR=1/3then find ar[PRQ]/ar[ACB].
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ΔABC ~ ΔPQR
If two triangles are similar then the ratio of their areas is equal to the square of the ratios of the corresponding sides of the triangles.
ar(BCA)/ar(PQR) = BC²/QR² = 1/9
ar(PRQ)/ar(BCA) = 9 : 1
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