Question

it is given that angle ABC=angle FDE of BA = 5cm, angle B= 40° and angle A=80°, then find the length of DF and also measurement of angle E​

Answer 1

Step-by-step explanation:

In △s APB and ABQ, we have

∠APB=∠AQB (Each 90

∘

)

∠PAB=∠QAB (AB bisect ∠PAQ)

AB=BA (common)

Therefore, △APB≅△ABQ (AAS)

⇒ BP=BQ (cpct)

Hence, B is equidistant from the anus of ∠A.

is your answer please mark me brainly