Question

. It is given that angle PQR = 72° and PQ is produced to point X If QY and QZ trisects angle XQR, find angle XQY and reflex angle XQZ.
Pls answer this question....​

Answer 1

Answer:

∠XYZ=64  

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YQ bisects ∠ZYP

∠XYZ+∠ZYP=180  

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(Linear Pair)

⇒64  

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+∠ZYP=180  

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∠ZYP=116  

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Also, ∠ZYP=∠ZYQ+∠QYP  

∠ZYQ=∠QYP   (YQ bisects∠ZYP)

⇒∠ZYP=2∠ZYQ

⇒2∠ZYQ=116  

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⇒∠ZYQ=58  

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=∠QYP

Now, ∠XYQ=∠XYZ+∠ZYQ

⇒∠XYQ=64  

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+58  

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⇒∠XYQ=122  

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Also, reflex ∠QYP=180  

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+∠XYQ

∠QYP=180  

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+122  

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⇒∠QYP=302  

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Step-by-step explanation:

Answer 2

Answer:

angle XQR=180-72=108

Angle XQZ =360-(36×2)=360-72=288

Angle XQY =108÷3= 36