Question

It is given that angleA=angleC and AB = BC. Prove that triangleABD is congruence to triangleCDE.​

Answer 1

Answer:

angle a = angle c ( given )

AB=BC( given )

angle D = angle D ( common )

so , it is congruent by ASA property

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Answer 2

Answer:

In the ∆ABC, angle A=angle C andAB=BC,BD is drawn perpendicular to AC.ThereforeBD is the median of the said triangle as it is an isosceles triangle. Therefore,we get,AB=BC,AD=CD(since BD is the median),and BD is the common side of both the triangles.Therefore∆ABD is congruent to ∆BDC ,according to S_S_S congruency chriteria.

Step-by-step explanation: