Question

It is given that for two events A and B , P(A) =3/8,P(A union B)=11/16 and P(A intersection B) =3/16. Find P(B).​

Answer 1

Answer:

P(B)=1/2

Step-by-step explanation:

P(AUB)=P(A)+P(B) -P(A INTERSECTION B)

11/16 = 3/8 + P(B) - 3/16

P(B) = 11/16 + 3/16 - 3/8 = 11/16 +(3/8)(1/2-1)

11/16 -3/16 = 8/16 =1/2

Answer 2

Answer:

p(a)+p(b)+p(a intersection b)=p(a union b)

3/8+p(b)+3/16=11/16

p(b)=11/16-3/8-3/16

=8/16-3/8

=8/16-3*2/8*2

=8/16-6/16

=8-6/16

= 2/16

p(b)=1/8