Question

It is given that in a group 3 students the probability of 2 students not having the same birthday is 0.992 wht is rhe probability that 2 students have the same birthday

Answer 1

Ans : the probability that the 2 students have the same birthday is

=1−0.992
=0.008

Answer 2

$here \: is \: your \: answer \: mate$

let E be the event of having the same birthday

P(E) =0.992

But P(E) +P = 1

P= 1-P(E)

= 1-P(E)

=1-0.992

=0.008