it is given that in a group of 3
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Let E be the event of having the same birthday.P(E) = 0.992⇒ P(E) + P(not E) = 1⇒ P(not E) = 1 – P(E)⇒ 1 - 0.992 = 0.008The probability that the 2 students have the same birthday is 0.008
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