Question

It is given that in a group of 3 student, the probability that the 2 students have the same birthday is 0.008. what Is the probability that the students not having the same birthday? ​

Answer 1

Answer:

The answer is 0.992

Step-by-step explanation:

The formula is P(E) +P(E`) =1

So given P(2) =0.008

So, P(E`) = 1-P(E)

= 1-0.008

= 0.992

Hence this the process

Answer 2

Step-by-step explanation:

P(E)=0.008

P(notE)=1-0.008

=0.992