It is given that in a group of 3 student, the probability that the 2 students have the same birthday is 0.008. what Is the probability that the students not having the same birthday?
Answers
Answered by
47
Answer:
The answer is 0.992
Step-by-step explanation:
The formula is P(E) +P(E`) =1
So given P(2) =0.008
So, P(E`) = 1-P(E)
= 1-0.008
= 0.992
Hence this the process
Answered by
12
Step-by-step explanation:
P(E)=0.008
P(notE)=1-0.008
=0.992
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