Question

It is given that in a group of 3 student , the probability of 2 students not having the same birthday is 0.992. What is the probability that the 2 students have the same birthday?​

Answer 1

Step-by-step explanation:

Let B≡ Event that 2 students do not have same birthday

∴P(B)=0.992

So, probability of 2 students having same birthday P(B)=1−P(B)

=1−0.992

=0.008

Video Explanation



Answer 2

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It is given that in a group of 3 student , the probability of 2 students not having the same birthday is 0.992. What is the probability that the 2 students have the same birthday?

$\huge\mathcal{\fcolorbox{aqua}{azure} {\red{ Answer}}}$

Probability that two students are not having same birthday = 0.992

Probability that two students are not having same birthday

= -1 Probability that two students are having same birthday

P (not same birthday) = 1-P (Same birthday)0.992= 1-P (same birthday)

P (same birthday) = 1-0.992

P ( same birthday) = 0.008

So probability that 2 students will have the same birthday is 0.008