Question

It is given that in a group of 3 students, the probability that the 2 students have the same birthday is 0.008. what is the probability that the students not having the same birthday?​

Answer 1

Answer:

Given, P(E) = 0.008

P(E) + P(not E) = 1

Or, P(not E) = 1 – 0.008 = 0.992

Step-by-step explanation:

Hope yo got your answer

Answer 2

Step-by-step explanation:

Given, P(E) = 0.008

P(E) + P(not E) = 1

Or, P(not E) = 1 – 0.008 = 0.992