Question

it is given that in a group of 3 students, the probability of 2 students not having the same birthday is 0.992.what is the probability that the 2 students have th esame birthday?​

Answer 1

Answer:

0.008 will be correct answer.

P(E) + P(notE)=1

0.992+P=1

P(notE)=0.008

Answer 2

Answer:

0.008

Step-by-step explanation:

Let P(Ē) be the probability that the 2 students do not share the same birthday, and P(E) be the probability that they share the same birthday.

P(Ē) = 0.992

Wkt, P(E) + P(Ē) = 1

∴ P(E) = 1 - P(Ē)

⇒ P(E) = 1 - 0.992

∴ P(E) = 0.008

So the probability that these 2 will share the same birthday is 0.008

Hope this helped!

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