Question

It is given that in a group of 3 students, the probability of 2 students not having the same birthday is 0.992. What is the probability that the 2 students have the same birthday?​

Answer 1

Answer:

0.008 is the answer for the given problem

Step-by-step explanation:

The probability of 2 students not having the same birthday =P(E)=0.992

The probability of 2 students having the same birthday =P(not E)=1-P(E)=1-0.992=0.008

(we know that P(E)+P(not E)=1)

Answer 2

Answer:

answer is 0.008

Probability that 2 students are not having same birthday=0.992

1-P, 1-0.992=0.008