Question

it is given that in a group of 3 students,the probability of 2 students not having the same birthday is 0.992.what is the probability that the 2 students have the same birthday?​

Answer 1

$heyy \: mate \\ \\ here \: is \: your \: answer$

let E be the event of having the same birthday

P(E) =0.992

But P(E) +P = 1

P= 1-P(E)

= 1-P(E)

=1-0.992

=0.008

Answer 2

Step-by-step explanation:

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