Question

It is given that in a group of 3 students, the probability of 2 students not having the same birthday is 0.992. The probability

that the 2 students have the same birthday will be

(a) 0.8

(e) 0,008

(b) 0.08

(d)0.008​

Answer 1

Answer:

b

Step-by-step explanation:

Let

B

≡ Event that 2 students do not have same birthday

∴P(

B

)=0.992

So, probability of 2 students having same birthday P(B)=1−P( B)

=1−0.992

=0.008

Answer 2

$option \: (d) \: is \: correct \: one$

let E be the event of having the same birthday

P(E) =0.992

But P(E) +P = 1

P= 1-P(E)

= 1-P(E)

=1-0.992

=0.008