Question

it is given that in a group of 3 students, the probability of 2 students not having the same birthday is 0.992. What is the probability rhat 2 students have the same birthday?

Answer 1

99.008 is the probability

Answer 2

let E be the event of having the same birthday

P(E) =0.992

But P(E) +P = 1

P= 1-P(E)

= 1-P(E)

=1-0.992

=0.008

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