Question

it is given that in a group of 3 students ,the probability of 2 students not having same birthday is 0.992.what is the probability that 2 students have same birthday ? .

Answer 1

for any event A
P(A)+P(not A)=1
here
P(2 students have same birthday)=1-0.992
=0.008

Answer 2

Given:

• Probability of 2 students in a group of 3 students not having same birthday = 0.992

To Find:

• Probability of the 2 students have same birthday.

Solution:

Let the event wherein 2 students having the same birthday be E

As per the given information,

Given, P(E) = 0.992

We know that,

P(E) + P(not E) = 1

Or, P(not E) = 1 – 0.992 = 0.008

∴ The probability that the 2 students have the same birthday is 0.008