Question

It is given that in a group of 3 students, the probability of 2 students not having the same birthday is 0.992. What is the probability that the 2 students have the same birthday?

Answer 1

SOLUTION :

Given : The probability of 2 students not having the same birthday = 0.992

Let E = Event of 2 students not  having same birthday

P(E) =  0.992

Let, (E¯) = event of 2 students having same birthday.

We know that,the sum of all the probabilities of all possible outcomes of experiment is 1.

P(Event) + P (not an Event) = 1.

P(E) +  P(E¯) = 1

P(E¯) = 1 -  P(E)

P(E¯)  = 1 – 0.992  

P(E¯)  = 0.008

Hence, the probability of 2 students have the same birthday is 0.008

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Answer 2

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