Question

it is given that in a group of 3 students the probability of two students not having the same birthday is 0.992 what is the probability that the two students have the same birthday

Answer 1

p(E)'=1-p(E)
p(E)'=1-.992
p(E)'0.008

Answer 2

let E be the event of having the same birthday

P(E) =0.992

But P(E) +P = 1

P= 1-P(E)

= 1-P(E)

=1-0.992

=0.008