Math, asked by danav21, 11 months ago

It is given that in a group of 3 students , the probablity that the 2 students have the dame birthday is 0.008 . what is the probablity that the students not having the same birthday ?

Answers

Answered by kinjalrps

1

Step-by-step explanation:

Probability that 2 Students are not having same birthday

P(E)= 0.008

Probability that 2 Students are having same birthday P(E)=1-P(E)

= 1 - 0.008

= 0.992

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