It is given that in a group of studies hebbly of 2 dents
same birthday is 992 What they had the
birthday
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Let
B
≡ Event that 2 students do not have same birthday
∴P(
B
)=0.992
So, probability of 2 students having same birthday P(B)=1−P(
B
)
=1−0.992
=0.008
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