Question

It is given that in group of 3 students the probability of 2 students not having the same birthday is 0.992. What is the probability that the two students have the same birthday

Answer 1

probability that the students have the same birthday is1-0.992=0.8

Answer 2

Answer:

Let E be the event of having the same birthday

P(E) = 0.992

But P(E) + P = 1

P = 1 – P(E) = 1 – 0.992 = 0.008