Question

it is given that in group of 3 students, the probability of two students having not same birthday is 0.992. what is the probability that 2 students have the same birthday?

Answer 1

Consider the first situation as A. Then, P(A)=0.992
what we have to find is, P(A')=1-P(A)=1-0.992=0.008

Answer 2

$here \: is \: your \: answer \: mate$

let E be the event of having the same birthday

P(E) =0.992

But P(E) +P = 1

P= 1-P(E)

= 1-P(E)

=1-0.992

=0.008