Question

It is given that t = px^2 + qx where x is displacement and t is time. The acceleration of particle at origin is?​

Answer 1

Answer:

Hope it will be helpful.

Explanation:

t=px

2

+qx

Differentiate with respect to time,

thus,1=2px.

dt

dx

+q.

dt

dx

or2pxv+qv=1(Atx=0,qv=1 orv=

q

1

)

Again differentiate with respect to time,

Hence,2pxa+2pv

2

+qa=0

Atx=0,putv=

q

1

,thuswegeta=

q

3

−2p

Answer 2

Answer:

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Correct answer is - 2p/q3

Explanation:

Differentiate two times and put x = 0