Question

It is given that tanA+cotA=2tanA+cotA=2

To find: The value of tan^2A+cot^2Atan2A+cot2A

Solution:

It is given that tanA+cotA=2tanA+cotA=2 , then

Squaring on both the sides, we have

(tanA+cotA)^2=4(tanA+cotA)2=4

tan^2A+cot^2A+2tanAcotA=4tan2A+cot2A+2tanAcotA=4

Now, because tanAcotA=1tanAcotA=1 , therefore the equation becomes,

tan^2A+cot^2A+2=4tan2A+cot2A+2=4

tan^2A+cot^2A=2tan2A+cot2A=2

Thus, the value of tan^2A+cot^2Atan2A+cot2A will be 2.

please tell me in this answer how it is happened tanAcotA=1

in 7th line.​

Answer 1

Answer:

Hello✌️✌️✌️✌️

Step-by-step explanation:

tanA = sinA/cosA

cotA = cosA/sinA

tanA*cotA = sinA/cosA * cosA/sinA = 1