it is given that the angle BAD equal to the angle C A and Angle B equal to the angle D prove that the angle ADB equal to angle AEC
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ΔABD and ΔACD,
AB = AC (Given)
∠B=∠C (because AB = AC)
and ∠ADB=∠ADC
Therefore, ΔABD≅ΔACD(AAS)
So, ∠BAD=∠CAD(CPCT)
△ABD and △ACD
AB=AC (given )
Then ∠ABD=∠ACD ( because AB=AC )
and ∠ADB=∠ADC=90( because AD⊥BC )
∴△ABD=△ACD
∠BAD=∠CAD
It is defective to use ∠ABD=∠ACD for proving this result
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