Math, asked by shriramarul, 10 months ago

it is given that the equation x^2+ax+20=0 has integer roots.what is the sum of all possible values of a?

(if u solved this question you are a genius)
(because this is a olympiad question)
pls give steps

Answers

Answered by amitnrw
13

Answer:

Sum of all possible Values of a  = 0

Step-by-step explanation:

it is given that the equation x^2+ax+20=0 has integer roots.what is the sum of all possible values of a

sum of roots = -a

Products of Roots = 20

as roots are integer =>

1 * 20  , 2 * 10  , 4 * 5

-1 * -20 , -2 * -10  , - 4 * -5  are possible comibinations

Possible Values of a = -21 , - 12 , -9 & 21 , 12 , 9

Sum of all possible Values of a  = 0

if we take only positive integers as roots

then -21 -12 - 9 = - 42  Sum of Possible values of a

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