Question

It is given that triangle ABC congruent it triangle FDE and AB = 5cm , angle B is 40° and angle A is 80°.Then find the value of DE and angle E

Answer 1

Answer:

The angle of E is $60^\circ$

Given:

It is given that triangle ABC congruent it triangle FDE and AB = 5cm , angle B is $40^\circ$ and angle A is $80^\circ$

To find:

Then find the value of angle E

Solution:

In a triangle abc, sum of angles of a triangle = 180 deg

$\angle A + \angle B + \angle C$ = 180

80 + 40 + $\angle C$= 180

$\angle C = 60^\circ$

Since the triangles are congruent ABC = FDE

$\angle C = \angle E.$

So, the angle of C is equal to E.

Result:

The angle of E is $60^\circ$

Answer 2

Answer:

In a triangle abc, sum of angles of a triangle = 180 deg

\angle A + \angle B + \angle C∠A+∠B+∠C = 180

80 + 40 + \angle C∠C = 180

\angle C = 60^\circ∠C=60

∘

Since the triangles are congruent ABC = FDE

\angle C = \angle E.∠C=∠E.

So, the angle of C is